4k/k^2-92/3+k

Solution for 4k/k^2-92/3+k equation:

D( k )

k^2 = 0

k^2 = 0

k^2 = 0

1*k^2 = 0 // : 1

k^2 = 0

k = 0

k in (-oo:0) U (0:+oo)

k+(4*k)/(k^2)-(92/3) = 0

k+(4*k)/(k^2)-92/3 = 0

1*k^1+4*k^-1-92/3*k^0 = 0

(1*k^2-92/3*k^1+4*k^0)/(k^1) = 0 // * k^2

k^1*(1*k^2-92/3*k^1+4*k^0) = 0

k^1

k^2+(-92/3)*k+4 = 0

k^2+(-92/3)*k+4 = 0

DELTA = (-92/3)^2-(1*4*4)

DELTA = 8320/9

DELTA > 0

k = ((8320/9)^(1/2)-(-92/3))/(1*2) or k = (-(-92/3)-(8320/9)^(1/2))/(1*2)

k = ((8320/9)^(1/2)+92/3)/2 or k = (92/3-(8320/9)^(1/2))/2

k in { (92/3-(8320/9)^(1/2))/2, ((8320/9)^(1/2)+92/3)/2} 

k in { (92/3-(8320/9)^(1/2))/2, ((8320/9)^(1/2)+92/3)/2 }